function - C++ - Variable Decrement -

heys.

i have code, sets table mystery reason. size 6x60. means sizey defined 6, , sizex 60.

void set_table(char** table) {     int i,j,k=0;      for(i=0;i<sizey;i+=3){         for(j=0;j<sizex;j++){             switch(k++%5){                 case 0:                     table[i][j]='|';                     break;                 case 1:                     table[i][j]=' ';                     break;                 case 2:                     table[i][j]=(char)((((k-2)/50)%10)+48);                     break;                 case 3:                     table[i][j]=(char)((((k-3)/5)%10)+48);                     break;                 case 4:                     table[i][j]=' ';                     break;                 default:                     continue;             }         }     } } 

i doing 3 variables, can see. question is, can 2 variables, or 1 ?

thanks in advance.

here's simplification you:

    switch(k++%5){         case 0:             table[i][j]='|';             break;         case 1:         case 4:             table[i][j]=' ';             break;         case 2:         case 3:             table[i][j]= '0';             break;         default:             continue;   } 

with c++, 1 case can fall another, such cases 1 , 2 above.

your expressions case 2 , 3 can simplified. i'll use case 2 example:
((((k-2)/50)%10)+48)
substituting 2 k yields
((((2-2)/50)%10)+48)
simplify:
((((0)/50)%10)+48)
0 divided zero, simplifying again:
(((0)%10)+48)
0 mod zero, since involves division:
((0)+48)
simplifying:
(48)
replacing equivalent character (since array char):
'0'