arrays - Strings are not sequence of characters in java? -

in java, why not possible convert string char array , vice versa?

why aren't comparable?

char matrixc[][] = {{'s', 't','a', 'c','k'},         {'o','v','e','r'},         {'f','l','o','w'}}; string [] matrixs = {"stack", "over","flow"};  // matrixs=matrixc     //not allowed...               if (matrixs.equals(matrixc) || matrixc.equals(matrixs)  ) {     system.out.print("true"); } else      system.out.print("false");       //output 

edited:

after research , digging, found answer of first question (why not possible convert string char array , vice versa?) in below link, explained roger_that. hint james. immutable

string immutable. meaning?

so, have separate string pool in java heap, stores , creates new string literals each time , refer them string objects accordingly.

still, have doubts comparison (i talking simple string , char sequence here, not 2d arrays)

why not there standard , simple method compare string , char seq? 1 way be, char data[] = {'a', 'b', 'c'}; string str="abc";

        if (str.length()==data.length && str.length()>0 )         {         (int i=0;i<str.length();i++)         {             if (str.charat(i)!=data[i])                 system.out.println("not equal");         }         }         else             system.out.println("not equal"); 

is there other simple/direct way this, except,

    char data[] = {'a', 'b', 'c'};     string str="abc";     string str1= new string(data);     if (str1.equals(str))     system.out.println("equal"); 

conclusion:

strings not sequence of characters in java.

they should remove line here https://docs.oracle.com/javase/tutorial/java/data/strings.html

strings

strings, used in java programming, sequence of characters. in java programming language, strings objects.

this line confusion started. :|

please correct understanding.

in c++ (which i'm guessing coming from) strings stored character arrays. not case in java. in java strings immutable objects rather char[].