python 3.x - Find and delete list elements if matching a string -

i have list of strings stringlist = ["elementone" , "elementtwo" , "elementthree"] , search elements contain "two" string , delete list list become stringlist = ["elementone" , "elementthree"]

i managed print them don't know how delete list using del because don't know index or using stringlist.remove("elementtwo") because don't know exact string of element containing "two"

my code far:

for x in stringlist:    if "two" in x:        print(x) 

normally when perform list comprehension, build new list , assign same name old list. though desired result, not remove old list in place.

to make sure reference remains same, must use this:

>>> stringlist[:] = [x x in stringlist if "two" not in x] >>> stringlist ['elementone', 'elementthree'] 

advantages:
since assigning list slice, it replace contents same python list object, reference remains same, thereby preventing bugs if being referenced elsewhere.

if below, lose reference original list.

>>> stringlist = [x x in stringlist if "two" not in x] >>> stringlist ['elementone', 'elementthree'] 

so preserve reference, build list object , assign list slice.

to understand subtle difference:

let take list a1 containing elements , assign list a2 equal a1.

>>> a1 = [1,2,3,4] >>> a2 = a1 

approach-1:

>>> a1 = [x x in a1 if x<2]  >>> a1 [1] >>> a2 [1,2,3,4] 

approach-2:

>>> a1[:] = [x x in a1 if x<2]  >>> a1 [1] >>> a2 [1] 

approach-2 replaces contents of original a1 list whereas approach-1 not.